Optimal. Leaf size=102 \[ -\frac {x^4 \sqrt {-1+a x} \sqrt {1+a x}}{2 a \cosh ^{-1}(a x)^2}+\frac {2 x^3}{a^2 \cosh ^{-1}(a x)}-\frac {5 x^5}{2 \cosh ^{-1}(a x)}+\frac {\text {Shi}\left (\cosh ^{-1}(a x)\right )}{16 a^5}+\frac {27 \text {Shi}\left (3 \cosh ^{-1}(a x)\right )}{32 a^5}+\frac {25 \text {Shi}\left (5 \cosh ^{-1}(a x)\right )}{32 a^5} \]
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Rubi [A]
time = 0.43, antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 5, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5886, 5951,
5887, 5556, 3379} \begin {gather*} \frac {\text {Shi}\left (\cosh ^{-1}(a x)\right )}{16 a^5}+\frac {27 \text {Shi}\left (3 \cosh ^{-1}(a x)\right )}{32 a^5}+\frac {25 \text {Shi}\left (5 \cosh ^{-1}(a x)\right )}{32 a^5}+\frac {2 x^3}{a^2 \cosh ^{-1}(a x)}-\frac {5 x^5}{2 \cosh ^{-1}(a x)}-\frac {x^4 \sqrt {a x-1} \sqrt {a x+1}}{2 a \cosh ^{-1}(a x)^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 3379
Rule 5556
Rule 5886
Rule 5887
Rule 5951
Rubi steps
\begin {align*} \int \frac {x^4}{\cosh ^{-1}(a x)^3} \, dx &=-\frac {x^4 \sqrt {-1+a x} \sqrt {1+a x}}{2 a \cosh ^{-1}(a x)^2}-\frac {2 \int \frac {x^3}{\sqrt {-1+a x} \sqrt {1+a x} \cosh ^{-1}(a x)^2} \, dx}{a}+\frac {1}{2} (5 a) \int \frac {x^5}{\sqrt {-1+a x} \sqrt {1+a x} \cosh ^{-1}(a x)^2} \, dx\\ &=-\frac {x^4 \sqrt {-1+a x} \sqrt {1+a x}}{2 a \cosh ^{-1}(a x)^2}+\frac {2 x^3}{a^2 \cosh ^{-1}(a x)}-\frac {5 x^5}{2 \cosh ^{-1}(a x)}+\frac {25}{2} \int \frac {x^4}{\cosh ^{-1}(a x)} \, dx-\frac {6 \int \frac {x^2}{\cosh ^{-1}(a x)} \, dx}{a^2}\\ &=-\frac {x^4 \sqrt {-1+a x} \sqrt {1+a x}}{2 a \cosh ^{-1}(a x)^2}+\frac {2 x^3}{a^2 \cosh ^{-1}(a x)}-\frac {5 x^5}{2 \cosh ^{-1}(a x)}-\frac {6 \text {Subst}\left (\int \frac {\cosh ^2(x) \sinh (x)}{x} \, dx,x,\cosh ^{-1}(a x)\right )}{a^5}+\frac {25 \text {Subst}\left (\int \frac {\cosh ^4(x) \sinh (x)}{x} \, dx,x,\cosh ^{-1}(a x)\right )}{2 a^5}\\ &=-\frac {x^4 \sqrt {-1+a x} \sqrt {1+a x}}{2 a \cosh ^{-1}(a x)^2}+\frac {2 x^3}{a^2 \cosh ^{-1}(a x)}-\frac {5 x^5}{2 \cosh ^{-1}(a x)}-\frac {6 \text {Subst}\left (\int \left (\frac {\sinh (x)}{4 x}+\frac {\sinh (3 x)}{4 x}\right ) \, dx,x,\cosh ^{-1}(a x)\right )}{a^5}+\frac {25 \text {Subst}\left (\int \left (\frac {\sinh (x)}{8 x}+\frac {3 \sinh (3 x)}{16 x}+\frac {\sinh (5 x)}{16 x}\right ) \, dx,x,\cosh ^{-1}(a x)\right )}{2 a^5}\\ &=-\frac {x^4 \sqrt {-1+a x} \sqrt {1+a x}}{2 a \cosh ^{-1}(a x)^2}+\frac {2 x^3}{a^2 \cosh ^{-1}(a x)}-\frac {5 x^5}{2 \cosh ^{-1}(a x)}+\frac {25 \text {Subst}\left (\int \frac {\sinh (5 x)}{x} \, dx,x,\cosh ^{-1}(a x)\right )}{32 a^5}-\frac {3 \text {Subst}\left (\int \frac {\sinh (x)}{x} \, dx,x,\cosh ^{-1}(a x)\right )}{2 a^5}-\frac {3 \text {Subst}\left (\int \frac {\sinh (3 x)}{x} \, dx,x,\cosh ^{-1}(a x)\right )}{2 a^5}+\frac {25 \text {Subst}\left (\int \frac {\sinh (x)}{x} \, dx,x,\cosh ^{-1}(a x)\right )}{16 a^5}+\frac {75 \text {Subst}\left (\int \frac {\sinh (3 x)}{x} \, dx,x,\cosh ^{-1}(a x)\right )}{32 a^5}\\ &=-\frac {x^4 \sqrt {-1+a x} \sqrt {1+a x}}{2 a \cosh ^{-1}(a x)^2}+\frac {2 x^3}{a^2 \cosh ^{-1}(a x)}-\frac {5 x^5}{2 \cosh ^{-1}(a x)}+\frac {\text {Shi}\left (\cosh ^{-1}(a x)\right )}{16 a^5}+\frac {27 \text {Shi}\left (3 \cosh ^{-1}(a x)\right )}{32 a^5}+\frac {25 \text {Shi}\left (5 \cosh ^{-1}(a x)\right )}{32 a^5}\\ \end {align*}
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Mathematica [A]
time = 0.12, size = 107, normalized size = 1.05 \begin {gather*} \frac {-16 a^4 x^4 \sqrt {-1+a x} \sqrt {1+a x}+64 a^3 x^3 \cosh ^{-1}(a x)-80 a^5 x^5 \cosh ^{-1}(a x)+2 \cosh ^{-1}(a x)^2 \text {Shi}\left (\cosh ^{-1}(a x)\right )+27 \cosh ^{-1}(a x)^2 \text {Shi}\left (3 \cosh ^{-1}(a x)\right )+25 \cosh ^{-1}(a x)^2 \text {Shi}\left (5 \cosh ^{-1}(a x)\right )}{32 a^5 \cosh ^{-1}(a x)^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 2.32, size = 123, normalized size = 1.21
method | result | size |
derivativedivides | \(\frac {-\frac {\sqrt {a x -1}\, \sqrt {a x +1}}{16 \mathrm {arccosh}\left (a x \right )^{2}}-\frac {a x}{16 \,\mathrm {arccosh}\left (a x \right )}+\frac {\hyperbolicSineIntegral \left (\mathrm {arccosh}\left (a x \right )\right )}{16}-\frac {3 \sinh \left (3 \,\mathrm {arccosh}\left (a x \right )\right )}{32 \mathrm {arccosh}\left (a x \right )^{2}}-\frac {9 \cosh \left (3 \,\mathrm {arccosh}\left (a x \right )\right )}{32 \,\mathrm {arccosh}\left (a x \right )}+\frac {27 \hyperbolicSineIntegral \left (3 \,\mathrm {arccosh}\left (a x \right )\right )}{32}-\frac {\sinh \left (5 \,\mathrm {arccosh}\left (a x \right )\right )}{32 \mathrm {arccosh}\left (a x \right )^{2}}-\frac {5 \cosh \left (5 \,\mathrm {arccosh}\left (a x \right )\right )}{32 \,\mathrm {arccosh}\left (a x \right )}+\frac {25 \hyperbolicSineIntegral \left (5 \,\mathrm {arccosh}\left (a x \right )\right )}{32}}{a^{5}}\) | \(123\) |
default | \(\frac {-\frac {\sqrt {a x -1}\, \sqrt {a x +1}}{16 \mathrm {arccosh}\left (a x \right )^{2}}-\frac {a x}{16 \,\mathrm {arccosh}\left (a x \right )}+\frac {\hyperbolicSineIntegral \left (\mathrm {arccosh}\left (a x \right )\right )}{16}-\frac {3 \sinh \left (3 \,\mathrm {arccosh}\left (a x \right )\right )}{32 \mathrm {arccosh}\left (a x \right )^{2}}-\frac {9 \cosh \left (3 \,\mathrm {arccosh}\left (a x \right )\right )}{32 \,\mathrm {arccosh}\left (a x \right )}+\frac {27 \hyperbolicSineIntegral \left (3 \,\mathrm {arccosh}\left (a x \right )\right )}{32}-\frac {\sinh \left (5 \,\mathrm {arccosh}\left (a x \right )\right )}{32 \mathrm {arccosh}\left (a x \right )^{2}}-\frac {5 \cosh \left (5 \,\mathrm {arccosh}\left (a x \right )\right )}{32 \,\mathrm {arccosh}\left (a x \right )}+\frac {25 \hyperbolicSineIntegral \left (5 \,\mathrm {arccosh}\left (a x \right )\right )}{32}}{a^{5}}\) | \(123\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{4}}{\operatorname {acosh}^{3}{\left (a x \right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^4}{{\mathrm {acosh}\left (a\,x\right )}^3} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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